A small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is modeled by the equation h(t) = –16t2 – 30t + 124, where t is the time in seconds. For which interval of time does the rock remain in the air?

t = 2

t > –2

t < 2

t > 2



WHICH ONE?? D:

Verified Answer :

Answer:

Third option is correct.

Step-by-step explanation:

The given model is

\(h(t)=-16t^2-30t+124\)

Where, h(t) is heigth of rock after time t (in seconds).

The initial height of rock is 124 ft.

The leading coefficient is negative. It means it is a downward parabola.

First we have to the x-intercepts of the function.

\(0=-16t^2-30t+124\)

Using quadratic formula, we get

\(t=\frac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}\)

\(t=-3.8752\) and \(t=2\)

It means rock remains in the air between \(-3.875.

The value of t can not be negative, therefore rock remains in the air between \(0.

Third option is correct.

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