The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
\(\frac{4C4\times48C9}{52C13}=0.00264106\)
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
\(0.00264106\times13=0.0343\)
The answer is 0.0343.
