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Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution.


A.) 0.333 M

B.) 0.751 M

C.) 1.50 M

D.) 3.00 M

Verified Answer :

taskmasters

Most of the information's required for solving this question is already given. Let us now focus on the problem in hand.

Grams/Molar Mass = Moles 


Molarity = Moles/Liters

The above formulas are important for solving this problem.

Number of moles of Nacl = 87.75/58.44

                                         = 1.50

Molarity = Number of moles of solute (here NaCl) / Volume of solution in Liters

Then

Volume of solution in Liters = Number of moles of solute (here NaCl)/Molarity

Volume of solution in Liters = 500/1500

                                            = 0.333 M

The correct option among all the options that are given in the question is the first option or option "A".

Molarity is defined as the number of moles of solute per 1 L of solvent.

the mass of NaCl in the solution is 87.75 g

number of moles of NaCl is calculated by dividing mass present by molar mass

number of NaCl moles = 87.75 g / 58.44 g/mol = 1.502 mol

the number of NaCl moles in 500 mL is - 1.502 mol

therefore number of NaCl moles in 1000 mL is - 1.502 mol/ 500 mL x 1000 mL/L = 3.004 mol

molarity of NaCl is - 3.004 M

answer is D. 3.00 M

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