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Select all the atoms whose ions have an electron configuration of nd6 (n = 3, 4, 5 ...).

For example, the 2+ ion for V ends the electron configuration with 3d 3.



A.) Fe

B.) Tl

C.) Ti

D.) Lu

E.) Os

F.) Rh

Verified Answer :

Electronic configuration of the following elements:

A) Fe - [Ar] 3d6 4s2
B) Tl - Xe 4f14 5d10 6s2 6p1
C) Ti - [Ar] 3d2 4s2
D) Lu - Xe 4f14 5d1 6s2
E) Os -  Xe 4f14 5d6 6s2
F) Rh -  Kr 4d8 5s1

Only A) Fe and E) Os have an electronic configuration of nd6.
A) Fe - 3d6
E) Os - 5d6

adioabiola

The atoms whose ions have an electron configuration of nd⁶ (where, n = 3, 4, 5....) are; Choice A and E; Fe and Os.

  • For Fe: electron configuration for Fe is [Ar] 3d⁶ 4s²

  • For Tl: A thallium atom has 81 electrons, arranged in the electron configuration [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p¹;

  • For Ti: Electron configuration for titanium is [Ar] 3d² 4s²

  • For Lu: Electron configuration of Lutetium ion is [Xe] 4f¹⁴ 5d¹ 6s²

  • For Os: Electron configuration of Osmium ion is; [Xe] 4f¹⁴ 5d⁶ 6s²

  • For Rh: Electron configuration of Rhodium is [Kr] 4d8 5s1.

Evidently, only Fe and Os are atoms whose ions have an electron configuration nd6.

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