Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

A.) 1.5%

B.) 3%

C.) 4.5%

D.) 9%

Question

nmitaaklivia nmitaaklivia

17-10-2016
Mathematics

Answered

Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

A.) 1.5%

B.) 3%

C.) 4.5%

D.) 9%

Verified Answer :

Related Questions

N8121152 plz help me

A sentence with the word fang

Which of the following is an example of the correlation of productivity and a positive attitude A James likes chatting with his coworkers but is easily distract

Mr Anderson is building a triangularshaped roof for his shed The triangle must be isosceles with its base noncongruent side measuring 14 feet

You are a manager and one of your team member asks why using slide presentations are a good idea Whats the best way to respond A Slide presentation use text onl

If you ever get caught in a rip current you should swim A against the rip current B parallel to the shoreline C with the rip current D toward the shoreline

what was the purpose of the Indian removal act

Athens united the greek citystates for protection under the athenian league delian league greece league

How old was albert einstein when he died

The point 10 lies on the graph of the function y2x28x6 true or false The point 10 lies on the graph of the function y2x28x6 true or false

Anonymous Anonymous · Answer 1 · 2016-10-21T18:31:15-04:00

The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to

SE = sqrt(pq/n) where p is the population proportion q is 1-p, and n is the sample size.

(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.)

The margin of error will be ZcSE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error.

For a 90% confidence interval, Zc is 1.645.

So the margin of error is 1.645 sqrt(.9.1/400), roughly .025. So your confidence interval would be around [.875, .925]

The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.

Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?A.) 1.5%B.) 3%C.) 4.5%D.) 9%

Verified Answer :

Related Questions

Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one active email account. What would the margin of error be for the population proportion?

A.) 1.5%

B.) 3%

C.) 4.5%

D.) 9%