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Verified Answer :

\(\displaystyle
\binom{5}{2}=\dfrac{5!}{2!3!}=\dfrac{4\cdot5}{2}=10\implies \text{D}\)

Answer:

Option D is correct.

Step-by-step explanation:

Total number of letters = c , o , u , n , t

We have to find: Numbers of ways in which two letters can be choose.

Combination is used to find numbers of ways.

\(^{n}\textrm{C}_{r}=\frac{n!}{r!\times(n-r)!}\)

Number of ways = \(^{5}\textrm{C}_{2}=\frac{5!}{2!\times(5-2)!}\)

\(=\frac{5!}{2!\times3!}=\frac{5\times4}{2}=5\times2=10\)

Therefore, Option D is correct.