What is the slope of the line that contains the point (4,6) and (12,3) ?
\(\frac{y_{2}-y_{1} }{x_{2}-x_{1}}\) = \(\frac{3 - 6}{12 - 4}\) = \(\frac{-3}{8}\).
The slope is \(\frac{-3}{8}\)x.
Slope = change in y / change in x.
Between (4, 6) and (12, 3) represents (x₁, y₁) and (x₂, y₂):
x₁ = 4, y₁ = 6, x₂ = 12, y₂ = 3
Slope = (y₂ - y₁) / (x₂ - x₁) = (3 - 6) / (12 - 4) = -3 / 8
Slope = -3/8
I hope this helps.