Solve for B. A = 3(B + C)
This is a literal equation first, divide 3 on both sides \(\frac{A}{3} = \frac{3(B+C)}{3}\)Next, subtract C on both sides \(\frac{A}{3} -C=B+C-C\)The answer is \(B= \frac{A}{3} -C\)
