How to solve:
1. Take f, which is 27, and plug that in for x.
\(\(f(27)=\) \(\sqrt{2x-5}\)\)
\(\(f(27)=\) \(\sqrt{2(27)-5}\)\)
2. multiply 27 by 2.
2 x 27 = 54
\((f(27)=\) \(\sqrt{54-5}\)\)
3. Subtract 5 from 54.
54 - 5 = 49
\((f(27)=\) \(\sqrt{49}\)\)
4. square root 49.
\((f(27)=\) \(7}\)\)
The answer is 7.
