How many moles of MgCl2 are there in 340 g of the compound?
To calculate the amount of the compound in the units of grams, we need to first obtain for the molar mass of the compound. We calculate as follows:
MgCl2 = 24.31 + (2 x 35.45) = 95.21 g/mol
340 g MgCl2 ( 1 mol / 95.21 g ) = 3.57 mol MgCl2
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Explanation:
Moles is defined as mass divided by molar mass.
Mathematically, Number of moles = \frac{mass}{molar mass}[/tex]
Therefore, it is given that mass is 340 g and molar mass of \(MgCl_{2}\) is 95.211 g/mol.
Hence, calculate number of moles as follows.
Number of moles = \(\frac{mass}{molar mass}\)
= \(\frac{340 g}{95.211 g/mol}\)
= 3.57 mol
Thus, we can conclude that there are 3.57 moles of MgCl2 are there in 340 g of the compound.