we have
\(y=\frac{1}{4} x-2\) -----> equation \(1\)
\(y=\frac{7}{4} x+4\) -----> equation \(2\)
Resolve the system
we know that
the solution of the system is the intersection of both graphs
Multiply by \(-1\) equation \(1\)
\(-y=-\frac{1}{4} x+2\)
Adds equation \(1\) and equation \(2\)
\(-y=-\frac{1}{4} x+2\)
\(y=\frac{7}{4} x+4\\ ------\)
\(0=\frac{6}{4}x +6\\ \\ 0=6x+24\\ 6x=-24\\ x=-4\)
find the value of y
\(y=\frac{7}{4}*(-4)+4\\ \\ y=-7+4\\ y=-3\)
the solution is the point \((-4,-3)\)
therefore
the answer is
The solution is the graph in the attached figure
