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Verified Answer :

Ckaranja

Taking point (0,-2) of graph one and replacing in the equation;
2x+3y=6
2(0)+3(-2)=6
-6=6
So graph isn't the required graph.

Taking point (0,2) of graph 2;
2x+3y=6
2(0)+3(2)=6
6=6
So, graph 2 is the required graph.

Answer:

Option (c) is correct.

Step-by-step explanation:

 Given : Equation of line 2x + 3y = 6

We have to graph the given equation

Consider the given equation of line 2x + 3y = 6

We first find the points for different values of x and y

And then plot these points.

1) Put x = 0

We get ,

3y = 6

y = 2

2) Put y = 0

We get,

2x = 6

x = 3

Thus, we get the points (0, 2) and (3,0)

Now plot these to obtain a line, we get, see attchment

Option (c) is correct.

View image athleticregina

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