Web Analytics
daisyromo
Answered

A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 104 kilograms, what is the value of the impulse?

Verified Answer :

Thank you for posting your question here in brainly. Below are the choices that can be found elsewhere.

A. 1.2 x 10^4

B. 2.2 x 10^5

C. 7.1 x 10^5

D. 3.6 x 10^4

The answer is C that means to say that the velocity after impact is still in the same direction as when the spaceship is falling.

Answer: The value of impulse will be \(7.1\times 10^5kg.m/s\)

Explanation:

Impulse is defined s the change in the momentum.

Mathematically,

\(\text{Impulse}=m\Delta v\)

where,

m = Mass of the object

\(\Delta v\) = Change in the velocity = \(v_2-v_1\)

Putting values in above equation, we get:

\(\text{impulse}=7.1\times 10^4kg(20-10)m/s=7.1\times 10^5kg.m/s\)

Hence, the value of impulse is \(7.1\times 10^5kg.m/s\)

Related Questions