Answer:
The volume of cone B is twice the volume of cone A.
Step-by-step explanation:
Cone A
Height of cone = 3 m
Radius of Cone = 2 m
Volume of cone = \(\frac{1}{3} \pi r^{2} h\)
= \(\frac{1}{3} \times 3.14 \times 2^{2} (3)\)
= \(12.56 m^3\)
Cone B
Height of cone = 6 m
Radius of Cone = 2 m
Volume of cone = \(\frac{1}{3} \pi r^{2} h\)
= \(\frac{1}{3} \times 3.14 \times 2^{2} (6)\)
= \(25.12 m^3\)
Now \(12.56 \times 2 = 25.12\)
Thus the volume of cone B is twice the volume of cone A.
