Answer:
The area of the doghouse is \(32.5\ ft^{2}\)
Step-by-step explanation:
we know that
The area of trapezoid is equal to
\(A=\frac{1}{2}(b1+b2)h\)
where
b1,b2 are the parallel bases of trapezoid
h is the height of trapezoid
in this problem we have
\(b1=5\ ft\)
\(b2=5+3=8\ ft\)
\(h=5\ ft\)
substitute
\(A=\frac{1}{2}(5+8)5=32.5\ ft^{2}\)
