Verified Answer :

apologiabiology

p^2-4p-32=(p-8)(p+4)

\(\frac{p^2-4p-32}{p+4}= \frac{(p-8)(p+4)}{p+4}=p-8\)
and p must not be equal to -4


B is answer

JcAlmighty

The answer is B. p – 8; p ≠ –4

The expression is: \(\frac{ p^{2}-4p-32}{p+4}\)
Since the the divisor cannot be zero, that means that p+4 cannot be zero:
p + 4 ≠ 0
⇒ p ≠ -4

Let's simplify this expression:
\(\frac{ p^{2}-4p-32}{p+4} = \frac{ (p+4)(p-8)}{p+4}\)

Now, cancel out (p+4) and you will get:
\(\frac{ (p+4)(p-8)}{p+4} = p-8\)

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