Answer:
Horizontal force is 16.97 N.
Explanation:
It is given that,
Mass of the block, m = 2 kg
It is on an incline at a 60 degree angle is held in equilibrium by a horizontal force. We need to find the magnitude of horizontal force. The force acting on the block is its weight mg.
The horizontal component of force is, \(F_x=mg\ sin\theta\)
The vertical component of force is, \(F_y=mg\ cos\theta\)
So, the horizontal component of force is,\(F_x=2\ kg\times 9.8\ m/s^2\ sin(60)\)
\(F_x=16.97\ N\)
So, the horizontal component of force is 16.97 N.
