If $396 is invested at an interest rate of 13% per year and is compounded continuously, how much will the investment be worth in 3 years?
if the interest is compound (yearly) then is calculated by
A = P (1+r)^(t)
then after 3 years the investment will worth
396(1.13)^3 = $571.38
Answer:
\(\$584.88\)
Step-by-step explanation:
we know that
The formula to calculate continuously compounded interest is equal to
\(A=P(e)^{rt}\)
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
e is the mathematical constant number
we have
\(t=3\ years\\ P=\$396\\ r=0.13\)
substitute in the formula above
\(A=\$396(e)^{0.13*3}=\$584.88\)