Answer:
The correct option is (B) The "k" value moves the graph up or down.
Step-by-step explanation:
Consider the provided function:
\(f(x)=log(x)\)
The graph of the provided function is shown in figure 1.
From figure 1, it can be seen that the domain of the function is all positive real numbers and not defined for the negative values.
The logarithmic function can be shift h units horizontally and k unit vertically for the equation:
\(f(x)=log_{b}(x+h)+k\)
Horizontal shift:
For h > 0, graph shift h units left and for h < 0, graph shift h units right.
For better understanding refer to the figure 2.
Vertical shift:
For k > 0, graph shift k units up and for k < 0 graph shift k units down.
For better understanding refer to the figure 3.
Hence, the correct option is (B) The "k" value moves the graph up or down.
