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SecretStupid

Step 1: Find the molar mass of Mn3(SO4)7.  


Mn3(SO4)7 = 3(54.94) + 7(32.07) + 28(16) = 837.31g  


Step 2: Calculate grams of Mn3(SO4)7 in the following manner:  


1.11 mol Mn3(SO4)7 (837.31g Mn3(SO4)7 /1 mol Mn3(SO4)7 ) = 929g Mn3(SO4)7  


mahima6824soni

There are 929 grams in 1.11 moles of manganese sulfate.

What are moles?

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

Step1: Calculate the molar mass of \(Mn_3(SO_4)_7.\)

3(54.94) + 7(32.07) + 28(16) = 837.31g  

Step2: Calculate the mass of \(Mn_3(SO_4)_7.\)

\(1.11 mol Mn_3(SO_4)_7 \dfrac{ (837.31g \;Mn_3(SO_4)_7 }{1 mol \;Mn_3(SO_4)_7 } = 929g\; Mn_3(SO_4)_7\)

Thus, the mass of 1.11 moles of \(Mn_3(SO_4)_7.\) is 929 grams.

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