Verified Answer :

moldm^_³*.moldm-³ =mol²dm^-6

Answer: \(mol^{-1}Ls^{-1}\)

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

\(Rate=k[A]^x[B]^y\)

k= rate constant

x = order with respect to A

y = order with respect to A

Given : \(Rate=k[A]^1[B]^1\)

\(k=\frac{rate}{[A]^1[B]^1}\)

Putting the units of various quantities:

\(k=\frac{rate}{[A]^1[B]^1}\)

\(k=\frac{molL^{-1}s^{-1}}{[molL^{-1}]^1[molL^{-1}]^1}\)

\(k=mol^{-1}Ls^{-1}\)

Thus units of rate constant are \(mol^{-1}Ls^{-1}\)