What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x? x = 5 x = 0 and x = 5
(5x^2-25x)/x
simplify
((x)(5)(x-5))/x=5(x-5)=5x-25=f(x)
(just fyi, that x we cancled is a hole)
set to zero
5x-25=0
5x=25
divide 5
x=5
zeroe is at x=5
or (5,0)
x=5 is answer
Answer:
x=5
Step-by-step explanation:
\(f(x)= \frac{5x^2-25x}{x}\)
To find out zeros we replace f(x) with 0
\(0= \frac{5x^2-25x}{x}\)
Now solve for x
first we divide the numerator by x
\(0=5x-25\)
Now we facor out GCF 5
\(0=5(x-5)\)
Divide by 5 on both sides
\(0=x-5\)
Add 5 on both sides
x= 5
zero of the function is x=5