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A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power source is 9.0 volts, what will the current be?

A0.062 amps
B16 amps
C0.56 amps
D0.32 amps
E39 amps

Verified Answer :

HomertheGenius

R 1,2 = 27.5 + 33.0 = 60.5 Ohms
1/ R 1,2,3 = 1/ 60.5 + 1 / 22 = 82.5 / 1331
R 1, 2, 3 = 1331 / 82.5 = 16.13 Ohms
I = U / R
I = 9 V / 16.13 Ohms = 0.557 A ≈ 0.56 A
Answer: C ) 0.56 Amps 

hamzaahmeds

This question involves the concept of Ohm's Law.

The voltage in the circuit will be "C. 0.56 A".

What is Ohm's Law?

According tot the Ohm's Law the current passing through a circuit is directly proportional to the voltage. Mathematically:

V = IR

where,

  • V = Voltage = 9 volts
  • I = current
  • R = Resistance

First, we need to find the equivalent resistance of the circuit. First the equivalent of the two resistors in series combination will be:

R₁ = 27.5 Ω + 33 Ω = 60.5 Ω

Now, this equivalent resistance is connected in parallel to other resistance. Therefore,

\(\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}\\\\\frac{1}{R}=\frac{1}{60.5\ \Omega}+\frac{1}{22\ \Omega}\\\\R = 16.13\ \Omega\)

Now, applying Ohm's Law:

\(V=IR\\\\I=\frac{V}{R}\\\\I = \frac{9\ volts}{16.13\ \Omega}\\\\\)

I = 0.56 A

Learn more about Ohm's Law here:

brainly.com/question/14796314

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