A candle is 17 in. tall after burning for 3 hours. After 5 hours, it is 15 in. tall. Write a linear equation to model the relationship between heigh h of the candle and time t. Predict how tall the candle will be after 8 hours.
For the linear equation you have two points (3, 17) and (5, 15) so the equation is: h-17=(15-17)/(5-3)*(t-3), solve for h= -t+20.
For predicting, only replace t=8 into you equation (h= -t+20) and you will get h=-8+20=12
Let
x------> the time in hours
y------> the height in inches
\(A(3,17)\\B(5,15)\)
Step \(1\)
Find the slope m of the linear equation between points A and B
we know that
The formula to calculate the slope between two points is equal to
\(m=\frac{(y2-y1)}{(x2-x1)}\)
substitutes the values
\(m=\frac{(15-17)}{(5-3)}\)
\(m=\frac{(-2)}{(2)}\)
\(m=-1\)
Step \(2\)
Find the equation of the line
we know that
the equation of the line in the point-slope form is
\(y-y1=m*(x-x1)\)
we have
\(m=-1\)
\(A(3,17)\)
substitute in the equation
\(y-17=-1*(x-3)\)
\(y=-x+20\) --------> this is the linear equation that model the relationship between height h of the candle and time t
Step \(3\)
Find the height for \(x=8\) hours
substitute the value of x in the linear equation
\(y=-8+20\)
\(y=12\ inches\)
The height of the candle will be \(12\ inches\) after \(8\ hours\)