Light traveling through air at 3.00 · 10^8 m/s reaches an unknown medium and slows down to 2.00 · 10^8 m/s. What is the index of refraction of that medium? n =
v 1= 3.00 · 10^8 m/s
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5
Answer
The index of refraction of medium is 1.5 .
Explanation:
Equation for index of refraction is given by .
\(n = \frac{c}{v}\)
Where n is index of refraction in medium , v is speed of light in the medium and c is the speed of light in air .
As given
Light traveling through air at \(3.00\times 10^8\) m/s reaches an unknown medium and slows down to \(3.00\times 10^8\) m/s.
\(c = 3.00\times 10^{8}\)
\(v = 2.00\times 10^{8}\)
Putting the values in the formula
\(n = \frac{3.00\times 10^{8}}{2.00\times 10^{8}}\)
Solving the above
n = 1.5
Therefore the index of refraction of medium is 1.5 .