We can find equals to the given components
\(f1= 200cos(60), 200sin(60)\)
Then you have to find equal for f2= 100cos(170) ,100sin(170) which is \(\ \textless \ -98.48, 17.36\ \textgreater \\)
Substract the vectors to find F3 coordinates \(= \ \textless \ 1.52, 190.56\ \textgreater \\)\(F3= \ \textless \ 100-98.48\ \textgreater \ , \ \textless \ 173.2+17.36\ \textgreater \\)
With theese new coordinates it is possible to find the direction and magnitude by using arc tan and square rooting. You should make \(X= 1.52 and Y=190.56\) and plug it to the arc tan function tan-\(1(190.56/1.52)\). You will obtain direction 89.54, then find magnitude of the square root of 36315.4 --\((1.52)^2 + (190.56)^2\)
