The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the trinomial to find a side of the square.

Aside = z + 27
Bside = z + 18
Cside = z + 9

Verified Answer :

A = s²
A =  z² + 18 z + 81
z² + 18 z + 81 = z² + 9 z + 9 z + 81 = z ( z + 9 ) + 9 ( z + 9 ) =
= ( z + 9 ) ( z + 9 ) = ( z + 9 )²
Answer:
C ) side = z + 9 

Answer:

option c is correct.

side = z+9

Step-by-step explanation:

Area of a square(A) is given by:

\(A = s^2\)

where,

s is the side of the square.

As per the statement:

A certain square has an area of  \(z^2 + 18z + 81.\)

⇒\(A = z^2 + 18z + 81\)

Substitute in [1] we have;

\(z^2 + 18z + 81 = s^2\)

Taking square root both sides we have;

\(\sqrt{z^2 + 18z + 81} =s\)

Using identity rule:

\((a+b)^2 =a^2+2ab+b^2\)

then;

\(\sqrt{z^2 + 2(1)(9)z + 9^2} =s\)

⇒\(\sqrt{(z+9)^2} =s\)

Simplify:

\(z+9 = s\)

or

s = z+9

Therefore,  a side of the square. is, z+9