λ\(= 550 * 10^{-9}\] m.
D = 3.50*10^-6 m.\)
\(d = 10 m.
m = 1
2x = ?\)
Then you need to find x when n=1
or
\(sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4\)
≈θ for θ<<1 , so θ=\(1.59x10^-4 radians\)
Then you can find rhe distance of bright fringe from the center:\(d= θD=1.59x10^-4x10m ≈ 1.6 mm\)
