Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'
The transformation is:
T : ( x , y ) → ( x + 2, y + 1 )
B ( 1, 3 ) → B ( 1 + 2, 3 + 1 ) ( 3, 4 )
B
d ( B B`) = √(( 3 - 1 )² + ( 4 - 3 )² )=
= √ (2² + 1²) = √ 5
Answer:
\(\sqrt{5}\ units\)
Step-by-step explanation:
we know that
The rule of the translation is equal to
\((x,y)-----> (x+2,y+1)\)
That means
The translations is \(2\) units to the right and \(1\) unit up
Let
\((x,y)\)-------> the coordinates of point B
\((x+2,y+1)\)------> the coordinates of point B'
Find the distance
the formula to calculate the distance between two points is equal to
\(d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}\)
substitute
\(d=\sqrt{((y+1)-y)^{2}+((x+2)-x)^{2}}\)
\(d=\sqrt{(1)^{2}+(2)^{2}}\)
\(d=\sqrt{5}\ units\)