Answer:
(C) 4, 12, 20, 28, 36, 44
Step-by-step explanation:
Given: \(a_{1}=4\) and \(a_{n}=a_{n-1}+8\)
To find: Find the first six terms of the sequence
Solution: Since, it is given that \(a_{1}=4\) and \(a_{n}=a_{n-1}+8\), then the first term is 4 and the common difference, d=8.
Thus, the next terms are:
\(a_{2}=a_{1}+8=4+8=12\),
\(a_{3}=a_{2}+8=12+8=20\),
\(a_{4}=a_{3}+8=10+8=28\),
\(a_{5}=a_{4}+8=28+8=36\) and
\(a_{6}=a_{5}+8=36+8=44\)
Thus, the first six terms of the sequence will be 4, 12, 20, 28, 36, 44.
thus, option C is correct.
