The value of x "\(\frac{5}{7}\)" and the value of y is "4".
Linear equation:
Given equation are:
\(7x-2y=-3\\\\14x+y=14\)
x,y=?
Let
\(7x-2y=-3..........................(a)\\\\14x+y=14.........................(b)\\\)
solve equation (a)
\(\to 7x-2y=-3\\\\\to 7x=-3+2y\\\\\to x=\frac{-3+2y}{7}................(d)\\\)
putting the value of x into equation (b):
\(\to 14(\frac{-3+2y}{7}) +y=14\\\\\to 2(-3+2y) +y=14\\\\\to -6+4y +y=14\\\\\to 5y=20\\\\\to y=\frac{20}{5}\\\\ \to y=4\)
Putting the value of y into the equation (d):
\(\to x=\frac{-3 +2(4)}{7}\\\\\to x=\frac{-3 +8}{7}\\\\\to x=\frac{5}{7}\\\\\)
Therefore the final value of x is "\(\frac{5}{7}\)" and y is "4".
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brainly.com/question/322601
