Answer:
Both right triangles are attached.
To find both similar triangles with a slope of 2/5, we have to remember that slope is related with the tangent of the angle of direction of the line.
So, in each graph, we have angle A, which has the relation:
\(tanA=m\); where \(m\) is the slope.
Now, we know by trigonometric reasons that:
\(tanA=\frac{opposite \ leg}{adjacent \ leg}=\frac{2}{5}=\frac{4}{10}\)
Where the proportion between triangles is 2.
