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your class hopes to collect at least 325 cans of food for the annual food drive. there were 135 cans donated the first week and 89 more the second week.

A;write an inequality that describes this situation. let C represent the number of cans of food that must be collected by the end of the third week for your class to meet your surpass its goal.

B; how may cans are needed to meet or surpass the goal

Verified Answer :

TaeKwonDoIsDead

They have collected \(135+89=224\) cans until now. To equal 325, they need \(325-224=101\) cans more.

A.

Let C be the number needed to equate atleast 325.

\(135+89+C\geq 325\)


B.

If we solve the inequality in part A, we can find minimum number of C to meet the goal of 325 cans.

\(135+89+C\geq 325\\224+C\geq325\\C\geq325-224\\C\geq101\)

So they need minimum 101 to complete the target and more than that to surpass.

ANSWER: 101 cans are needed to meet the goal and more than that to surpass the goal.

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