Answer:
\(v_x= 1.61 \frac{m}{s}\)
Explanation:
Conceptual analysis
Since the velocity has a vector character, in the attached figure we define a rectangular coordinate plane to decompose the total velocity (v) that is in the direction θ with the horizontal.
\(v_x\) and \(v_y\) are the sides of a right triangle that has hypotenuse v.
The total velocity vector is defined as follows:
\(v=v_x i+v_y j\) Formula (1)
Where:
\(v_x\) = vcosθ: Formula (2) magnitude of velocity in x direction
\(v_y\) = vsinθ: Formula (3) magnitude of velocity in y direction
i: is positive (+) to the right of the x axis and negative (-) to the left of the x axis
j: is positive (+) upward of the x axis and negative (-) downward of the y axis
Known data
v = 1.7 m/s
θ = 18.5°
Problem development
We replace the data in formula (2) to calculate the magnitude of \(v_x\):
\(v_x=1.7 \frac{m}{s} * cos(18.5degrees)\)
\(v_x= 1.61 \frac{m}{s}\)
