What is the value of (–7 3i) – (2 – 6i)? –9 9i –9 – 3i –5 – 3i –5 9i
Answer:
Value of \((-7+3i)-(2-6i)= -9 + 9i\)
Step-by-step explanation:
To find the value of the give expression: \((-7+3i)-(2-6i)\)
Property of subtraction of complex number states that the subtract \(z_1-z_2\) of two complex numbers \(z_1 = a+ib\) and \(z_2= c+id\) is defined as the complex number i.e
\(z_1 -z_2 = (a+ib)-(c+id) =(a-c) +i(b-d)\)
It is observed that while subtracting two complex numbers the real and imaginary parts of the system is obtained by subtracting the real and imaginary parts of the summands.
Now;
\((-7+3i)-(2-6i) = (-7-2) +(3-(-6))i = -9 + (3+6)i = -9+9i\)
Therefore, the value of \((-7+3i)-(2-6i)\) is, -9 + 9i.