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A plane traveled from California and back. It took one hour longer on the way out than it did on the way back. The plane's average speed out was 300 mph. The average speed on the way back was 350 mph. How many hours did the trip out take?

A8 hours
B6 hours
C7 hours
D13 hours

Verified Answer :

koolkid98

i would want to say c), but im not 50% sure. hope this helps :)

Blacklash

Answer:

Option D is the correct answer.

Step-by-step explanation:

Let x be the one way distance and t be the time out.

Time taken for back = t-1

We have plane's average speed out was 300 mph and average speed on the way back was 350 mph.

That is

           \(\frac{x}{300}=t\texttt{ and }\frac{x}{350}=t-1\)

Dividing both equations

             \(\frac{\frac{x}{300}}{\frac{x}{350}}=\frac{t}{t-1}\\\\350t-350=300t\\\\t=7\texttt{ hours}\)

Time taken for back = t-1 = 7-1 = 6 hours.

Total time taken = 7 + 6 = 13 hours

Option D is the correct answer.

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