Answer:
\(-24\cdot x^{7}\)
Step-by-step explanation:
We have been given an expression \((-2x^2)^3\cdot3x\). We are asked to find the product of our given expression.
Using exponent property \((a^b)^c=a^{b\cdot c}\), we will get:
\((-2x^2)^3\cdot 3x=-2^3\cdot x^{2\cdot 3}\cdot3x\)
\((-2x^2)^3\cdot 3x=-8\cdot x^{6}\cdot 3x\)
\((-2x^2)^3\cdot 3x=-8\cdot 3\cdot x^{6}\cdot x\)
\((-2x^2)^3\cdot 3x=-24\cdot x^{6}\cdot x\)
Using exponent property \(a^b\cdot a^c=a^{b+c}\), we will get:
\((-2x^2)^3\cdot 3x=-24\cdot x^{6+1}\)
\((-2x^2)^3\cdot 3x=-24\cdot x^{7}\)
Therefore, the product of our given expression would be \(-24\cdot x^{7}\).
