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The area, A, of a rectangle is 120x2 + 78x – 90, and the length, l, of the rectangle is 12x + 15. Which of the following gives the width, w, of the rectangle?

A.9x + 4

B.10x – 19

C.10x – 6

D.8x – 6

Verified Answer :

The answer will be C. 10x -6
(10x-6)(12x+15)=120x^2+78x-90

Let

L--------> the length side of a rectangle

W--------> the width side of a rectangle

we know that

the area of a rectangle is equal to

\(A=L*W\)

\(A= 120x^{2} + 78x - 90\)

\(L=12x+15\)

To find the width side W of the rectangle we need to find the roots of the equation of the area

so

Equate to zero the area and find the roots

\(120x^{2} + 78x - 90=0\)

using a graph tool

see the attached figure

\(x=-1.25\\ x=0.6\)

\(120x^{2} + 78x - 90=120*(x+1.25)*(x-0.6)\)

\(120*(x+1.25)*(x-0.6)=6*(4x+5)*(5x-3)\)

\(6*(4x+5)*(5x-3)=3*(4x+5)*2*(5x-3)\)

\(3*(4x+5)*2*(5x-3)=(12x+15)*(10x-6)\)

therefore

the answer is

the width of the rectangle is equal to \((10x-6)\)

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