Answer: Correct name will be is aluminum bromide
Explanation:
In a molecular formula ,\(AlBr_3\)
Aluminium atoms present = 1
Bromine atoms present = 3
Charge on aluminium is +3 and charge on bromine is -1.
While naming:
- Name of the cation is written first. Simple name of the element is written
- After name of cation name of an anions written with suffix 'ide' in the end.
So, the name of \(AlBr_3\) will be aluminium bromide.
