For this case we have the following polynomial:
\(3x ^ 2 + 11x - 4
\)
Rewriting the exponent term equal to 1 we have:
\(3x ^ 2 + 12x - x - 4
\)
Then, grouping terms we have:
\((3x ^ 2 + 12x) - (x + 4)
\)
By doing 3x common factor in the first parenthesis we have:
\(3x (x + 4) - (x + 4)
\)
Then, by making the expression common factor within the parentheses we have:
\((x + 4) (3x-1)
\)
Answer:
The factors that jenna needs to model for the sides are:
\((x + 4) (3x-1)\)
