we see that the the parabola opens up since directix is below the focus
for an parabolla opening up/down with vetex at (h,k) and the distance from teh vertex to the focus is p
\((x-h)^2=4p(y-k)\)
the distance from vertex to directex is the same as from focus to directix
from (-5,5) and y=-1
that is a vertical distance of 6
vertex is in the middle
6/2=3
5-3=2
the vertex is at (-5,2)
the distance is 3
\((x-(-5))^2=4(3)(y-(2))\)
\((x+5)^2=12(y-2)\)
\(y=\frac{1}{12}(x+5)^2+2\)
