What is the cube root of b^27?
i think the answer is b^9bc you just divide the 27 by 3
Answer:
\(b^{9}\)
Step-by-step explanation:
we have
\(\sqrt[3]{b^{27}}\)
we know that
\(\sqrt[3]{b^{27}}=(b^{27})^{\frac{1}{3}}=(b})^{\frac{27}{3}} =b^{9}\)
