Answer:
We have to add 9 on both sides of the equation.
Step-by-step explanation:
The given equation is \(x^2 - 6x = 1\)
Let's identify the value of "b" by comparing the general form of quadratic equation \(ax^2 + bx + c = 0\)
Here the value of b = -6
To make it perfect square trinomial, we have to divide b value by 2 and make it square. Then we have to add it on both side of the equation.
(b/2) = (-6/2)^2 = (-3)^2 = -3*-3 = 9
So we need to add 9 on both sides of the equation in order to make it perfect square.
\(x^2 - 6x + 9 = 1 + 9\\(x -3)^2 = 10\)
