Solve for x. what is 1900=1300(1+.0625)^x?
First rearrange as:\(\frac{1900}{1300}=1.0625^{x}\)Taking logs of both sides, we get:\(log\ \frac{1900}{1300}=x\ log1.0625\)\(x=\frac{log\frac{1900}{1300}}{log\ 1.0625}=6.26\)x = 6.26.
1900 = 1300(1 + 0.0625)ˣ 1900 = 1300(1.0625)ˣ 1300 1300 1⁶/₁₃ = (1.0625)ˣ㏑(1⁶/₁₃) = ln((1.0625)ˣ)㏑(1⁶/₁₃) = x㏑(1¹/₁₆) ln(1¹/₁₆) ln(1¹/₁₆) 6.26 ≈ x