How many moles of bromine (Br) atoms are in a sample of 2.03 × 1024 atoms?
The mole is simply an Avogadros number of anything( in this case Br atoms)
The Avogadro number is 6.022 x 10^23.
So no of moles = No of atoms / 6.022 x 10^23 = 2.03 x 10^24 / 6.022 x 10^23 = 3.37 Moles.
Answer: The number of moles of bromine atoms in the given amount of sample is 3.37 moles.
Explanation:
According to mole concept:
1 mole of an element contains \(6.022]times 10^{23}\) number of atoms
We are given:
Number of bromine atoms = \(2.03\times 10^{24}\)
As, \(6.022]times 10^{23}\) atoms form 1 mole of an element.
So, \(2.03\times 10^{24}\) atoms will form = \(\frac{1}{6.022\times 10^{23}}\times 2.03\times 10^{24}=3.37moles\) of bromine element.
Hence, the number of moles of bromine atoms in the given amount of sample is 3.37 moles.