2sin^(-2490)+tan 1410
2sin²(-2490)+tan 1410=2sin²(-330-6360)+tan (330+3360)==2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)==2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
