A projectile is fired at an inclination of 45° to the horizontal, with a muzzle velocity of 96 feet per second. The height h of the projectile is given by the following where x is the horizontal distance of the projectile from the firing point.
The horizontal distance is given by: x = vcos(∅) t x = 96cos(45) t The maximum height attained is when upwards velocity is 0 v² - u² = 2ah 0 - (vsin(∅))² = 2 -9.81 h h = (96sin(45))²/(2 9.81) h = 235 feet
