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An object accelerates to a velocity of 34m/s over a time of 1.3 s the acceleration it experienced was 15 m/s squared what was the initial velocity

Verified Answer :

v=v0+at=>v0=v-at=34-15•1,3=34-19,5=14,5m/s

Answer:

Initial velocity, u = 14.5 m/s

Explanation:

It is given that,

Final velocity of the object, v = 34 m/s

Time, t = 1.3 s

Acceleration of the object, \(a=15\ m/s^2\)

To find,

Initial velocity of the object

Solution,

Let u is the initial velocity of the object. It can be calculated using the first equation of motion as :

\(v=u+at\)

\(u=v-at\)

\(u=34-15\times 1.3\)

u = 14.5 m/s

So, the initial velocity of the object is 14.5 m/s.

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