Answer:
\(\frac{r(6)}{s(6)}=\frac{17}{13}\)
Step-by-step explanation:
Given: r(x)=3x-1 and s(x)= 2x+1
We have to find \(\frac{r}{s}(6)\)
That is to find \(\frac{r}{s}(6)=\frac{r(6)}{s(6)}\)
first find r (6) and s(6) , then substitute, we get,
r(6)
r(x) = 3x - 1
Put x = 6 , we get
r(6) = 3(6) -1 = 18 - 1 = 17
s(6)
s(x) = 2x + 1
Put x = 6 , we get
s(6) = 2(6) + 1 = 12 + 1 = 13
Thus,
\(\frac{r(6)}{s(6)}=\frac{17}{13}\)
