meh
ok so when have sqrt, try to square both sides
\(\sqrt{2x-1}=2+ \sqrt{x-4}\)
square both sides
\(2x-1=4+4 \sqrt{x-4}+x-4\)
\(2x-1=x+4 \sqrt{x-4}\)
mnus x both sides
\(x-1=4 \sqrt{x-4}\)
square oth sides
x^2-2x+1=16(x-4)
x^2-2x+1=16x-64
minus (16x-4) from both sides
x^2-18x+65=0
factor
(x-5)(x-13)=0
set each to zero
x-5=0
x=5
x-13=0
x=13
x=5 and 13
